Total number of enol forms possible for the c | vedclass

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(B) The reaction between $CH_3MgBr$ and $CH_3CH_2COCl$ produces $CH_3COCH_2CH_3$ $(2-Butanone)$.$2-Butanone$ $(CH_3-CO-CH_2-CH_3)$ can form enols by r

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$3$

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(B) The reaction between $CH_3MgBr$ and $CH_3CH_2COCl$ produces $CH_3COCH_2CH_3$ $(2-Butanone)$.$2-Butanone$ $(CH_3-CO-CH_2-CH_3)$ can form enols by removing an $\alpha$-hydrogen from either side of the carbonyl group.$1.$ Removal of $\alpha$-hydrogen from the $CH_3$ group gives $CH_2=C(OH)-CH_2CH_3$ ($1$ form).$2.$ Removal of $\alpha$-hydrogen from the $CH_2$ group gives $CH_3-C(OH)=CH-CH_3$. This form exhibits geometrical isomerism,resulting in $cis$ and $trans$ isomers ($2$ forms).Total number of enol forms = $1 + 2 = 3$.

Total number of enol forms possible for the compound formed during the given reaction will be (including stereoisomers):
$CH_3MgBr + CH_3CH_2COCl \to$

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Total number of enol forms possible for the compound formed during the given reaction will be (including stereoisomers):$CH_3MgBr + CH_3CH_2COCl \to$